237 lines
4.8 KiB
C
237 lines
4.8 KiB
C
#include <stdio.h>
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int isLeapYear(int year)
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{
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return (year % 4 == 0 && year % 100!= 0) || (year % 400 == 0);
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}
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int getDaysInMonth(int year, int month)
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{
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int daysInMonth[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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if (month == 1 && isLeapYear(year))
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{
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return 29;
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}
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return daysInMonth[month];
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}
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void printCalendarHeader()
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{
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printf(" Sun Mon Tue Wed Thu Fri Sat\n");
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}
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void printMonth(int year, int month)
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{
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int z;
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int days = getDaysInMonth(year, month);
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int firstDayOfMonth = (year * 365 + (year - 1) / 4 - (year - 1) / 100 + (year - 1) / 400) % 7;
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int i,day;
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for (i = 0; i < month; i++)
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{
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firstDayOfMonth += getDaysInMonth(year, i);
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}
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firstDayOfMonth %= 7;
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printCalendarHeader();
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for (i = 0; i < firstDayOfMonth; i++)
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{
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printf(" ");
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}
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for (day = 1; day <= days; day++)
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{
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printf("%5d", day);
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if ((firstDayOfMonth + day) % 7 == 0)
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{
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printf("\n");
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}
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}
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}
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int main(void)
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{
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int choice;
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printf("1. 查询对应年份日历\n");
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printf("2. 查询对应日期星期\n");
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printf("3. 判断所输入年份是否为闰年\n");
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printf("4. 退出\n");
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scanf("%d", &choice);
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int year,month,week,day,day_x,day_z=0,c=0;
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int i,j,k,l,m,n,b;
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char a;
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start:
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switch (choice)
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{
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case 1:
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printf("请输入年份：");
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scanf("%d", &year);
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int month;
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int z;
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printf("1.单列输出\n2.双列输出\n");
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scanf("%d",&z);
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for (month = 0; month < 12; month++)
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{
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printf("\n %d月\n", month + 1);
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printMonth(year, month);
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}
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break;
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case 2:
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printf("请输入该查询的年份：\n");
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scanf("%d",&year);
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printf("请输入该查询的月份：\n");
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scanf("%d",&month);
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printf("请输入该查询的日期: \n");
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scanf("%d",&day);
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if(year<1 || year>9999)
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{
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printf("输入年份错误，请重新输入:");
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scanf("%d",&year);
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}
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if(month<1 || month>12)
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{
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printf("输入月份错误，请重新输入:");
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scanf("%d",&month);
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}
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if(day<1 || day>31)
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{
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printf("输入日期错误，请重新输入：");
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scanf("%d",&day);
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}
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if(month<3)
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{
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year--;
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month+=12;
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}
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if(year==1582 && month==10)
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{
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day_x=21;
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if(day>=15)
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{
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k=year%100;j=year/100;l=day;m=month;
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n=(l+(26*(m+1)/10)+k+(k/4)+(j/4)+5*j)%7;
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switch(n)
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{
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case 0:
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printf("星期六");
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break;
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case 1:
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printf("星期日");
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break;
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case 2:
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printf("星期一");
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break;
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case 3:
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printf("星期二");
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break;
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case 4:
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printf("星期三");
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break;
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case 5:
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printf("星期四");
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break;
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case 6:
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printf("星期五");
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break;
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}
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break;
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}
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else
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{
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l=day+10;
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k=year%100;j=year/100;m=month;
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n=(l+(26*(m+1)/10)+k+(k/4)+(j/4)+5*j)%7;
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switch(n)
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{
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case 0:
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printf("星期六");
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break;
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case 1:
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printf("星期日");
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break;
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case 2:
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printf("星期一");
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break;
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case 3:
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printf("星期二");
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break;
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case 4:
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printf("星期三");
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break;
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case 5:
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printf("星期四");
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break;
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case 6:
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printf("星期五");
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break;
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}
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}
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break;
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}
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else
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{
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k=year%100;j=year/100;l=day;m=month;
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n=(l+(26*(m+1)/10)+k+(k/4)+(j/4)+5*j)%7;
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switch(n)
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{
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case 0:
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printf("星期六");
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break;
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case 1:
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printf("星期日");
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break;
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case 2:
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printf("星期一");
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break;
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case 3:
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printf("星期二");
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break;
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case 4:
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printf("星期三");
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break;
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case 5:
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printf("星期四");
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break;
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case 6:
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printf("星期五");
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break;
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}
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}
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break;
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case 3:
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printf("请输入年份：\n");
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scanf("%d",&year);
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if(year%4==0 && year%100!=0 || year%400==0)
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{
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printf("%d是闰年\n",year);
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}
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else
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{
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printf("%d不是闰年\n",year);
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}
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break;
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case 4:
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a=choice;
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if(a==4)
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{
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return 0;
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}
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break;
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default:
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printf("无效的选择，请重新输入(1~4):\n");
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scanf("%d",&choice);
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do
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{
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if(choice>4 || choice==0)
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{
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printf("无效选择，请重新输入:");
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continue;
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}
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else
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{
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break;
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}
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}
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while(choice<=4 && choice!=0);
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goto start;
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}
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return 0;
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}
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