UIT2024_Calendar/stu2024/数技2402张一寒.cpp

#include "stdio.h"
#include "math.h"
#include "stdlib.h" 
int main(void)
{
	printf("1.查询对应年份的日历\n2.查询某具体日期的星期\n3.查询对应年份是否为闰年\n"); 
	int num,year,mon,day,a,b,d;
	printf("**********************\n");
	printf("输入查询项目编号\n");
	scanf("%d",&num);
	system("cls");//清屏
	if(num==1)
	{
		int nums;
		printf("1.单列输出\n2.双列输出\n");
		printf("输入想要表现形式的序号：\n");
		scanf("%d",&nums);
		if(nums==1)
		{
		printf("输入年份"); 
		scanf("%d",&year);
	    a=(year%4==0&&year%100!=0||year%400==0);
	    b=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400+1)%7;//每年一月一日是周几
	    if(year!=1582)
	    {
	    for(mon=1;mon<=12;mon++)
	    {
	    	switch(mon)//判每月天数
	    	{
	    		case 1:
	    			day=31;
	    			break;
	    		case 2:
	    			if(a==1)
	    			day=29;
	    			else
	    			day=28;
	    			break;
	    		case 3:
	    			day=31;
	    			break;
	    		case 4:
	    			day=30;
	    			break;
	    		case 5:
	    			day=31;
	    			break;
	    		case 6:
	    			day=30;
	    			break;
	    		case 7:
	    			day=31;
	    			break;
	    		case 8:
	    			day=31;
	    			break;
	    		case 9:
	    			day=30;
	    			break;
	    		case 10:
	    			day=31;
	    			break;
	    		case 11:
	    			day=30;
	    			break;
	    		case 12:
	    			day=31;
	    			break;
	    	} 
	    	printf("----------------%d月---------------\n",mon);
		    printf("   日   一   二   三   四   五   六\n");//一个中文占两个字节
	    switch(b)//判位置
	    {
	    	case 1:
	    		printf("%5c",'\40');
	    		break;
	    	case 2:
	    		printf("%10c",'\40');
	    		break;
	    	case 3:
	    		printf("%15c",'\40');
	    		break;
	    	case 4:
	    		printf("%20c",'\40');
	    		break;
	    	case 5:
	    		printf("%25c",'\40');
	    		break;
	    	case 6:
	    		printf("%30c",'\40');
	    		break;
	    }
		for(int i=1,j=b;i<=day;i++,j++)
		{
			printf("%5d",i);
			if(j%7==6)
			printf("\n");
		}
		 b=(b+day)%7;//下个月的第一天周几
		 printf("\n");
	    }
	    }
    	else if(year==1582)//1582的单列输出
    	{
    		d=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400+11)%7; 
    		for(mon=1;mon<=12;mon++)
	    {   
	    	switch(mon)
	    	{
	    		case 1:
	    			day=31;
	    			break;
	    		case 2:
	    			if(a==1)
	    			day=29;
	    			else
	    			day=28;
	    			break;
	    		case 3:
	    			day=31;
	    			break;
	    		case 4:
	    			day=30;
	    			break;
	    		case 5:
	    			day=31;
	    			break;
	    		case 6:
	    			day=30;
	    			break;
	    		case 7:
	    			day=31;
	    			break;
	    		case 8:
	    			day=31;
	    			break;
	    		case 9:
	    			day=30;
	    			break;
	    		case 10:
	    			day=31;
	    			break;
	    		case 11:
	    			day=30;
	    			break;
	    		case 12:
	    			day=31;
	    			break;
	    	} 
	    	printf("----------------%d月---------------\n",mon);
		    printf("   日   一   二   三   四   五   六\n");
	    switch(d)
	    {
	    	case 1:
	    		printf("%5c",'\40');
	    		break;
	    	case 2:
	    		printf("%10c",'\40');
	    		break;
	    	case 3:
	    		printf("%15c",'\40');
	    		break;
	    	case 4:
	    		printf("%20c",'\40');
	    		break;
	    	case 5:
	    		printf("%25c",'\40');
	    		break;
	    	case 6:
	    		printf("%30c",'\40');
	    		break;
	    }
		for(int i=1,j=d;i<=day;i++,j++)
		{   
			if(mon==10)
			{
				if(i>4&&i<15)
				continue;
				printf("%5d",i);
				if(i==16||i==23||i==30)
				{
					printf("\n");
				}
	     	}
	     	else 
	     	{
			    printf("%5d",i);
			    if(j%7==6)
			    printf("\n");
		    }
		}
		if(mon==10)
		{
		    d=(d+day+ 1)%7;//下个月第一天是周几
		    printf("\n");
	    }
	        d=(d+day)%7;//下个月第一天是周几
		    printf("\n");
	    }
    	}
    }
    else if(nums==2)//双列
    {
    	printf("输入年份"); 
		scanf("%d",&year);
	    a=(year%4==0&&year%100!=0||year%400==0);
	    b=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400+1)%7;//每年一月一日是周几
	    for(mon=1;mon<=12;mon++)
	    {
	    	switch(mon)//判每月天数
	    	{
	    		case 1:
	    			day=31;
	    			break;
	    		case 2:
	    			if(a==1)
	    			day=29;
	    			else
	    			day=28;
	    			break;
	    		case 3:
	    			day=31;
	    			break;
	    		case 4:
	    			day=30;
	    			break;
	    		case 5:
	    			day=31;
	    			break;
	    		case 6:
	    			day=30;
	    			break;
	    		case 7:
	    			day=31;
	    			break;
	    		case 8:
	    			day=31;
	    			break;
	    		case 9:
	    			day=30;
	    			break;
	    		case 10:
	    			day=31;
	    			break;
	    		case 11:
	    			day=30;
	    			break;
	    		case 12:
	    			day=31;
	    			break;
	   	   }
	   	   printf("----------------%d月----------------|",mon++);
	   	   printf("----------------%d月----------------\n",mon);
		   printf("   日   一   二   三   四   五   六");
		   printf("   日   一   二   三   四   五   六\n");
		   switch(b)//判位置
	    {
	    	case 1:
	    		printf("%5c",'\40');
	    		break;
	    	case 2:
	    		printf("%10c",'\40');
	    		break;
	    	case 3:
	    		printf("%15c",'\40');
	    		break;
	    	case 4:
	    		printf("%20c",'\40');
	    		break;
	    	case 5:
	    		printf("%25c",'\40');
	    		break;
	    	case 6:
	    		printf("%30c",'\40');
	    		break;
	   }
		for(int i=1,j=b;i<=day;i++,j++)
		{
			printf("%5d",i);
			if(j%7==6)
			printf("\n");
		}
		 b=(b+day)%7;//下个月的第一天周几
		 printf("\n");
		}
	}
    }
	else if(num==2)//判星期
	{
		int year,mon,day,a,b,c,d,e ;
		printf("输入想要查询的具体日期\n");
		printf("年：\n");
		scanf("%d",&year);
		printf("月：\n");
		scanf("%d",&mon);
		printf("日：\n");
		scanf("%d",&day);
		int arr[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
		if(year==1582)
		arr[10]=21;
		a=(year%4==0&&year%100!=0||year%400==0);
		b=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400+1)%7;  
		d=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400+11)%7;   
		if(year>1582)
		{
			if(a==1)
				arr[2]=29;
				for(int i=0;i<mon;i++)
				{
					b=(b+arr[i])%7;
					c=(b+day-1)%7;
		    	}
    	}
		else if(year<1582)
		{
			if(a==1)
			arr[2]=29;
			for(int i=0;i<mon;i++)
			{
				d=(d+arr[i])%7;
				c=(d+day-1)%7;
			}
		}	
		else if(year==1582)
		{
			if(mon<=10&&day<5)
			{
			for(int i=0;i<mon;i++)
			{
				d=(d+arr[i])%7;
				c=(d+day-1)%7;
			}
			}
			else if(mon==10&&15<=day<=31)
			{
			for(int i=0;i<mon;i++)
			{ 
				d=(d+arr[i])%7;
				c=(d+day-11)%7;
	    	}
	    	}
			else if (mon>10)
			{
			for(int i=0;i<mon;i++)
			{
				d=(d+arr[i])%7;
				c=(d+day-1)%7;
			}
		    }
	    }
		switch(c)
	    	{
	    		case 0:
	    			printf("星期日");
	    			break;
	    		case 1:
	    			printf("星期一");
	    			break;
	    		case 2:
                    printf("星期二");	    	
	    			break;
	    		case 3:
	    			printf("星期三");
	    			break;
	    		case 4:
	    			printf("星期四");
	    			break;
	    		case 5:
	    			printf("星期五");
	    			break;
	    		case 6:
	    			printf("星期六");
	    			break;
	        }
    }
	else  if(num==3)
    {
	    printf("输入年份");
	    scanf("%d",&year);
	if(year%4==0&&year%100!=0||year%400==0)
	{
		printf("闰年"); 
		return 0;
	} 
	 else
	 	printf("不是闰年"); 
    } 
	return 0;
}