107 lines
2.4 KiB
C++
107 lines
2.4 KiB
C++
#include<stdio.h>
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int year1(int y)
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{
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if((y%4==0)&&(y%100!=0)||y%400==0)
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return 366;
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else
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return 365;
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}
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int main(void){
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int command;
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printf("|-----------欢迎使用------------|\n");
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printf("|1.查询对应的星期 |\n");
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printf("|2.判断是否为闰年 |\n");
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printf("|3.查询对应的日历 |\n");
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printf("|4.退出 |\n");
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printf("|-------------------------------|\n");
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do{
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printf("请输入您选择的功能：");
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scanf("%d",&command);
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switch(command)
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{
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case 1:
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int year,month,day,week;
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printf("请输入年月日(中间用空格分隔开):");
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scanf("%d%d%d",&year,&month,&day);
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if(month==1||month==2){
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month+=12;
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year--;}
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week=(day+2*month+3*(month+1)/5+year+year/4-year/100+year/400)%7;
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switch(week){
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case 0:
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printf("星期一\n");
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break;
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case 1:
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printf("星期二\n");
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break;
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case 2:
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printf("星期三\n");
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break;
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case 3:
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printf("星期四\n");
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break;
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case 4:
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printf("星期五\n");
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break;
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case 5:
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printf("星期六\n");
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break;
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case 6:
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printf("星期日\n");
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break;
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}
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break;
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case 2:
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int x;
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printf("请输入年份");
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scanf("%d",&x);
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if(x%4==0&&x%100!=0||x%400==0)
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printf("闰年\n");
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else
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printf("不是闰年\n");
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break;
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case 3:
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{
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int y,i,j,sum=0,z;
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int begin,week;
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int days[12]={31,28,31,30,31,30,31,31,30,31,30,31};
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printf("请输入年份:");
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scanf("%d",&y);
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printf("1.单列输出 2.双列输出\n");
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printf("请输入:",z);
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scanf("%d",&z) ;
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if(z==1)
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for(i=1;i<y;i++)
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sum+=year1(i);
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week=(sum+1)%7;
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if(year1(y)==366)
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days[1]=29;
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printf("\n%d年日历如下:\n\n",y);
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for(i=0;i<12;i++)
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{
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printf(" %d月 \n",i+1);
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printf("周日 周一 周二 周三 周四 周五 周六\n");
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printf("==================================\n");
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begin=1;
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for(j=0;j<week;j++)
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printf("");
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while(begin<=days[i])
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{
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printf("%5d",begin);
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begin++;
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week=(week+1)%7;
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if(week%7==0)
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printf("\n");
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}
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printf("\n\n");}
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break;}
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case 4:
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printf("感谢您的使用，再见");
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break;
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default:
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printf("无此功能，请再次输入\n");}
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}
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while(command!=4);
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return 0;
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}
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